Math, asked by vatsala4, 8 months ago

solve:. ...... Shobo's mother present age is six times Shobo's present age.Shobo's age 6 years from now will be one third of his mother's present age. What are their present ages?​

Answers

Answered by TheValkyrie
1

Answer:

\bigstar{\bold{Age\:of\:Shobo=6\:years}}

\bigstar{\bold{Age\:of\:mother=36\:years}}

Step-by-step explanation:

\Large{\underline{\underline{\bf{Given:}}}}

  • Present age of mother = 6 times Shobo's age
  • Age of Shobo after 6 years = 1/3 of mother's present age

\Large{\underline{\underline{\bf{To\:Find:}}}}

  • Present age of Shobo and mother

\Large{\underline{\underline{\bf{Solution:}}}}

→ Let present age of mother be x

→ Let present age of mother be y

→ By given,

  x = 6y---(1)

→ Shobo's age after 6 years = y + 6

→ Also by given,

  y + 6 = 1/3 (x)

→ Substitute the value of x from equation 1

  y + 6 = 1/3 (6y)

→ Cancelling 6 and 3

  y + 6 = 2y

  2y - y = 6

         y = 6

→ Hence Shobo's age is 6 years.

\boxed{\bold{Age\:of\:Shobo=6\:years}}

→ Substitute the value of y in equation 1

  x = 6y

  x = 6 × 6

  x = 36

→ Hence Shobo's mother is 36 years old.

\boxed{\bold{Age\:of\:mother=36\:years}}

\Large{\underline{\underline{\bf{Verification:}}}}

→ Present age of mother = 6 times Shobo's age

  x = 6 y

  36 = 6 × 6

  36 = 36

→ Age of Shobo after 6 years = 1/3 of mother's present age

  y + 6 = 1/3 × x

  6 + 6 = 1/3 × 36

  12 = 12

→ Hence verified.

Answered by jamunagovind1978
0

Answer:

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Step-by-step explanation:

Shobo's mother age is 6 times of Shobo. After 5yrs Shobo's age will be 1/3 of his mothers present age. We will solve this linear equation in two Variable to get the ages of Shobo and his mother. Hence Shobo's present age is 5yrs and present age of mother will be 5 × 6 = 30yrs.

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