Math, asked by khushalkumavat74, 7 months ago

solve simultaneous 5p+7p=26;2p+3q=11

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Answered by dooncambridgeschools

Answer:

$let \: p \: and \: q \: be \: x \: n \: y \\ \times 5x + 7y = 26by2 \\ the \: second \: by \: 5 \\ 10x + 14y = 52 \\ 10x15y = 55 \\ - x = - 3 \\ x = 3$

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solve simultaneous 5p+7p=26;2p+3q=11​

Answers

solve simultaneous 5p+7p=26;2p+3q=11