solve simultaneous equation 2/x+2/3y=1/6, 3/x+2/y=0
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y=0.9 because x divided 2 is 2, 2 divided by 3 is 1.1. Then, 2+1.1y =3. 2-2 cancels, and you're left with 1.1y = 1. divide on both sides, and you get 1 divided by 1.1 and that equals 0.9
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Hi,
2/x + 2/3y = 1/6
divide each term with 2 , we get
1/x + 1/3y = 1/12 ---( 1 )
3/x + 2/y = 0----( 2 )
multiply equation ( 1 ) with 3 , and subtract
from ( 2 ) , we get
3/x + 1/y = 1/4 ---( 3 )
3/x + 2/y = 0---( 2 )
_______________
( 1/y - 2/y ) = 1/4
-1/y = 1/4
-y = 4
y = - 4
Put y = - 4 in equation ( 2 ) ,
2/x + 2/( - 4 ) = 0
2/x - 1/2 = 0
2/x = 1/2
4 = x
Therefore ,
x = 4 , y = -4
I hope this helps you.
: )
2/x + 2/3y = 1/6
divide each term with 2 , we get
1/x + 1/3y = 1/12 ---( 1 )
3/x + 2/y = 0----( 2 )
multiply equation ( 1 ) with 3 , and subtract
from ( 2 ) , we get
3/x + 1/y = 1/4 ---( 3 )
3/x + 2/y = 0---( 2 )
_______________
( 1/y - 2/y ) = 1/4
-1/y = 1/4
-y = 4
y = - 4
Put y = - 4 in equation ( 2 ) ,
2/x + 2/( - 4 ) = 0
2/x - 1/2 = 0
2/x = 1/2
4 = x
Therefore ,
x = 4 , y = -4
I hope this helps you.
: )
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