Math, asked by shridhar778, 9 months ago

solve simultaneous equation 2x+3y=-41 and x-5y=11​

Answers

Answered by shaikhfaisalf304
4

Step-by-step explanation:

2x+3y=-41_________(1)

x-5y=11_________(2)

eq 2to multiple 2

it gives

2x-10y=22________(3)

eq 3&1 ki subtract

2x+3y=-41

2x-10y=22

_________

0+13y=-63

y= -63/-13

y=4.5..

Answered by Anonymous
4

Answer:

x=-13.25;y=-4.85 please mark brilliant and thank

Step-by-step explanation:

2x+3y=-41.................(1)

x-5y=11......................(2)

from equation (2)

x=11+5y......................(3)

Putting the value of x in equition (3)

2 (11+5y)+3y=-41

22+10y+3y=-41

22+13y=-41

13y=-41-22

13y=-63

y=-63/13

y=-4.85

Putting y=-4.85 in equition(3)

x=11+5×-4.85

x=11+-24.25

x=-13.25

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