solve simultaneous equation
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let 1/3x+y = A
1/3x-y = B
hence the eqn became
A+B=3/4
4A + 4B =3/ ---1 eqn
also
A/2 - B/2= 1/8
A - B = 1/4
4A-4B = 1---2 eqn
by solving 1eqn and 2nd we get
A = 1/2
B = 1/4
now by putting the value of A and B we get
3x+y = 1/2
3x-y = 1/4
now by solving both the eqn we get
x= 1/8
y= 1/8
thank you
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