Question

Solve simultaneous equation
3a+5b=26; a+5b=22

Answer 1

Answer:

a = 2

b = 4

Step-by-step explanation:

3a + 5b = 26 ..............1.

a + 5b = 22...............2.

BY SUBTRACTING EQUATION 2 FROM 1 WE GET

2a = 4

a = 4/2

:. a = 2

substitute a = 2 in 2.

2 + 5b = 22

:. 5b = 22 - 2

:. 5b = 20

:. b = 20/5

:. b = 4

THEREFORE (a , b) = (2 , 4) IS THE SOLUTION FOR THE GIVEN SIMULTANEOUS EQUATION .

Answer 2

Answer:

3a + 5b = 26; .....(I)

a + 5b = 22 .....(II)

Subtracting (II) from (I)

2a = 4

⇒ a = 2

Putting the value of a = 2 in (II)

5b = 22 - 2 = 20

⇒b = 20/5

=4

Thus, a = 2 and b = 4.