Math, asked by tanishka36, 1 year ago

solve simultaneous equation by method of elimination

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Answered by ChelsiNegi
12
Hope it's helps...........
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Answered by abhi569
12
9)-

2x-6+3y -15=0

2x +3y =15+6

2x +3y =21 --1equation

5(x-1)+4(y-4)=0

5x-5 +4y -16=0

5x+4y =16+5

5x+4y =21 --2equation

____________________

2x +3y =21 * 5
5x +4y =21 *2

10x +15y =104
10x +8y =42
- - -

7y =63

y =63/7

y =9

Putting the value of y in equation 1

2x +3y =21

2x +(3*9) =21


2x +27=21

2x =21-27

x= -6/2

x= -3
___________________________



11)-

3x +2y=11
2x-3y = -10

3x+2y =11 multiply by 3

2x-3y = -10 multiply by 2
________________

9x +6y =33
4x -6y = -20

13x = 13

x=13/13

x=1

Putting the value of x in 2x-3y =-10


2 -3y = -10

2+10=3y

12=3y

12/3=y

4=y
___________________,,

x=1

y =4



I hope this will help you



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