Math, asked by nazzu30, 11 months ago

solve simultaneous equations using by elimination method
x-y =75_____eq1
4x-6y = 95 _____eq2​

Answers

Answered by paavanikohli
4

Answer:

y=102.5 x=177.5

Step-by-step explanation:

x-y=75___eq1

4x-6y=95___eq2

multiplying eq1 by 4

4x-4y= 300__eq3

eq3-eq2

4x - 4y =300

-4x-(-6y)= -95

_______________

2y= 205

y= 205/2= 102.5

x-y=75

x=75+y

x=75+102.5

x= 177.5

Answered by ShreyaSingh31
25

\bf{\huge{\bf{\underline{\boxed{\sf{\blue{Answer:}}}}}}}

\bf{\underline{\underline{\sf{\green{Given\:equations\::}}}}}

  1. x - y = 75
  2. 4x - 6y = 95

\bf{\underline{\underline{\sf{\green{To\:find\::}}}}}

  • Value of x and y.

\bf{\underline{\underline{\sf{\green{Solition\::}}}}}

Multiply equation 1 by 4,

=> x - y = 75 ---> 1

=> 4 × x - 4 × y = 4 × 75

=> 4x - 4y = 300 ----> 3

Solve equations 3 and 2 simultaneously by elimination method.

Subtract equation 3 from equation 2,

....+ 4x - 4y = 300 ----> 3

- ( + 4x - 6y = 95 -----> 2

-----------------------------

2y = 205

y = \frac{205}{2}

y = 102.5

Substitute y = 102.5 in equation 1,

=> x - y = 75

=> x - 102.5 = 75

=> x = 75 + 102.5

=> x = 177.5

\bf{\large{\bf{\underline{\boxed{\sf{\purple{Solution\::\:(x, y) =(177.5,102.5}}}}}}}

\bf{\huge{\bf{\underline{\boxed{\sf{\pink{Verification:}}}}}}}

  1. x - y = 75
  2. 4x - 6y = 95

For equation 1 :-

x = 177.5

y = 102.5

Substitute these values in the equation,

=> x - y = 75

=> 177.5 - 102.5 = 75

=> 75 = 75

LHS = RHS.

For second equation :-

=> 4x - 6y = 95

=> 4 (177.5 ) - 6 ( 102.5 ) = 95

=> 710 - 615 = 95

=> 95 = 95

LHS = RHS

Hence verified.

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