solve simultaneous linear equation by substitution 5y-4x=32;8y+2x=26
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5y -4x = 32 ________(1) ×1
8y+ 2x =26 ×2 ______(2) ×2
then we have
5y-4x=32
16y+4x= 52
add both equation
21y=84
y=84/21
y=4
put the value of y in equation ( 1)
20 -4x =32
-4x=32-20
-4x =12
x=12/-4 = 6
x=6 and y= 4
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