Solve, sin 2theta= cos 3theta
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Answer:
Ф = ( 2 n + 1 / 2 ) π / 5 or ( 2 n - 1 / 2 ) π , n € I
Step-by-step explanation:
Given :
cos 3 Ф = sin 2 Ф
Rewrite as :
cos 3 Ф = cos ( π / 2 - 2 Ф )
On comparing we get :
3 Ф = π / 2 - 2 Ф
3 Ф + 2 Ф = π / 2
5 Ф = π / 2
We know if :
cos Ф = cos α
= > Ф = 2 n π ± α , n € I
Taking positive sign :
Ф = ( 2 n + 1 / 2 ) π / 5
Now taking negative sign :
Ф = ( 2 n - 1 / 2 ) π
Therefore , Ф = ( 2 n + 1 / 2 ) π / 5 or ( 2 n - 1 / 2 ) π .
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