Question

Solve sin^2X+6cosX=6 in the interval 0360 to one decimal place

Answer 1

Step-by-step explanation:

1 - cos²x + 6 cos x =6

or, cos²x - 6 cos x +5 =9

or, cos²x - cos x - 5cos x + 5 = 0

or, cos x(cos x - 1) - 5(cos x - 1)= 0

or, (cos x - 5)(cos x - 1) = 0

or, cos x= 1

or, x = 0°/360°