solve :-
Sin[arc cos1by2]
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Heya!!
Sin ( Cos-¹ 1/2 ) = ?
Put Cos-¹ (1/2) = x we have
Sin ( x ) = ? ... ( i )
1/2 = Cos ( x )
Sin² x + Cos² x = 1
Sin² x = 1 - Cos² x
Sin x = √(1 -1/4 )
x = Sin-¹ (√3/2 )
Now, put value of x in i we have
Sin ( Sin-¹ √3/2 )
= √3/2
amitrawat26:
thanks a lot...
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