Question

Solve sin (B+C)/2= cos A/2


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Answer 1

the sum of the angles of a triangle is 180°

Therefore,

angle A + Angle B + Angle C = 180°

Angle B + Angle C = 180°-A

Then,

Angle B + Angle C/2 = 90°-A/2

Therefore,

Sin(B+C/2) = Sin(90°-A/2)

=> Sin(B+C/2) = Cos A/2 [ Sin(90°-theta) = cos theta]

Hence,

LHS = RHS

Sin (B+C/2) = Cos A/2

HOPE IT WILL HELP YOU. :-)

Answer 2

Step-by-step explanation:

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