Math, asked by TT432, 1 month ago

Solve : (sinθ+cosθ)(secθ+cosecθ)=2+secθcosecθ

Answers

Answered by jasminejoseph54321
1

Answer:

457+--645--6778

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Answered by dhruvijain821
0

Answer:

(sinθ+cosθ)(secθ+cosecθ)

⇒(sinθ+cosθ)(

cosθ

1

+

sinθ

1

)

⇒(sinθ+cosθ)(

cosθsinθ

sinθ+cosθ

)

cosθsinθ

(sinθ+cosθ)

2

cosθsinθ

sin

2

θ+cos

2

θ+2sinθcosθ

cosθsinθ

1

+2

⇒2+secθcosecθ

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