Solve : (sinθ+cosθ)(secθ+cosecθ)=2+secθcosecθ
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1
Answer:
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Answered by
0
Answer:
(sinθ+cosθ)(secθ+cosecθ)
⇒(sinθ+cosθ)(
cosθ
1
+
sinθ
1
)
⇒(sinθ+cosθ)(
cosθsinθ
sinθ+cosθ
)
⇒
cosθsinθ
(sinθ+cosθ)
2
⇒
cosθsinθ
sin
2
θ+cos
2
θ+2sinθcosθ
⇒
cosθsinθ
1
+2
⇒2+secθcosecθ
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