Question

solve : sin x + sin Y =1 cos 2x- cos2Y=1 ​

Answer 1

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$sin \: x + sin \: y = 1 \\ = > sin \: x + sin \: y = 90 \\ = > x + y = 90 - - - - - - (1) \\ = > cos \: 2x - \cos2y = 1 \\ = > cos \: 2x - cos \: 2y = cos \: 0 \\ = > 2x - 2y = 0- - - - - - - (2) \\ \small\underline{ \underline{ \mathfrak\red{now \: (1 \times 2) = > }}} \\ 2x + 2y = 180 - - - - (3) \\ \huge\underline{ \underline{ \mathfrak\red{(3 - 2)}}} = > \\ 2x + 2y - 2x + 2y = 180 - 0 \\ = > 4y = 180 \\ = > y = 45 \\ \small\underline{ \underline{ \mathfrak\purple{value \: of \: y \: put \: in \: (1)}}} \\ = > x + 45 = 90 \\ = > x = 45$

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