Solve : sin2 0+ sin 0 = 1 and find 0.
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Answer:
sin2 2x = 0
sin 2x = 0
⇒ 2x = nπ, where, n = 0, ± 1, ± 2, ± 3,……., [Since, we know that θ = nπ, n ∈ Z is the general solution of the given equation sin θ = 0]
⇒ x = nπ2, where, n = 0, ± 1, ± 2, ± 3,…….
Therefore, the general solution of the equation sin2 2x = 0 is x = nπ2, where, n = 0, ± 1, ± 2, ± 3
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