solve sin63 cos27 +cos63 sin27
philheath:
sin 27 sin(90-27) + cos(90-63) cos 27
its nothing but expansion of sin(A + B) therefore it's sin(63 + 27) that is sin(90) that is 1
sin^2 27+ cos ^2 27
=1
yeh
but it is more eAsy steps to understand
Answers
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Hiii friend,
Sin63° × Cos27° + Cos63° × Sin27°
=> Sin63° × Cos(90-63°) + Cos63° × Sin(90-63°).
=> Sin63° × Sin63° + Cos63° × Cos63° [ Cos(90-theta) = Sin theta].
=> Sin²63° + Cos²63°
=> 1
HOPE IT WILL HELP YOU.... :-)
Sin63° × Cos27° + Cos63° × Sin27°
=> Sin63° × Cos(90-63°) + Cos63° × Sin(90-63°).
=> Sin63° × Sin63° + Cos63° × Cos63° [ Cos(90-theta) = Sin theta].
=> Sin²63° + Cos²63°
=> 1
HOPE IT WILL HELP YOU.... :-)
thank u
I am was very confused
both methods are correct... but this one is long
welcome
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