Solve Sin75°????????
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11
Your answer is --
Using the trigonometry identity
sin(A+B) = sinA cosB + sinB cosA
Now, we write
sin75° = sin(45°+30°) = sin45°×cos30° + sin30°× cos45°
= (1/√2×√3/2) + (1/2×1/√2)
= √3/2√2 + 1/2√2
= (√3+1)/2√2
Hence, value of sin75° = (√3+1)/2√2
【 Hope it helps you 】
Using the trigonometry identity
sin(A+B) = sinA cosB + sinB cosA
Now, we write
sin75° = sin(45°+30°) = sin45°×cos30° + sin30°× cos45°
= (1/√2×√3/2) + (1/2×1/√2)
= √3/2√2 + 1/2√2
= (√3+1)/2√2
Hence, value of sin75° = (√3+1)/2√2
【 Hope it helps you 】
Answered by
8
I hope it will helps u
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