Math, asked by JTalha89, 1 year ago

Solve Sin75°????????

Answers

Answered by Anonymous
11
Your answer is --

Using the trigonometry identity

sin(A+B) = sinA cosB + sinB cosA

Now, we write

sin75° = sin(45°+30°) = sin45°×cos30° + sin30°× cos45°

= (1/√2×√3/2) + (1/2×1/√2)

= √3/2√2 + 1/2√2

= (√3+1)/2√2

Hence, value of sin75° = (√3+1)/2√2

【 Hope it helps you 】
Answered by Anonymous
8
I hope it will helps u
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