Question

solve sinA+1/cosA. To 1/secA-tanA

Answer 1

$\frac{sinA+1}{cosA}= \frac{1}{secA-tanA}$

now conjugate, L.H.S

$\frac{xsinA+1}{cosA} ( \frac{-cosA}{-cosA} ) =\ \textgreater \ \frac{cosA}{1-sinA}$

now R.H.S 

$\frac{1}{ \frac{1}{cosA}- \frac{sinA}{cosA} }$

$\frac{1}{ \frac{1-sinA}{cosA} }$

$\frac{cosA}{1-sinA}$
 
so now we come to know that L.H.S =R.H.S 

we didn't send anything to the other side, we just simplified it 

$\frac{cosA}{1-sinA} = \frac{cosA}{1-sinA}$

Answer 2

PLEASE SEE THE ATTACHED PICTURE ABOVE. ..............☺