Question

solve: sinx cosx dx+ siny cost dy =0​

Answer 1

Answer:

⇒sinxsinydy=−cosxcosydx

⇒∫tanydy=−∫cotxdx

⇒logsecy=−logsinx+logc

′

⇒logsecy=logcosecx+logc

′

⇒logsecy=log(cosecx×c

′

)

⇒

cosy

1

=

c

′

sinx

1

sinx=ccosy