Question

solve sinx+sin2x+sin3x+sin4x=0​

Answer 1

Answer:

Step-by-step explanation:

sin x + sin 2x + sin 3x + sin 4x = 0

( sin 3x + sin x) + ( sin 2x + sin 4x ) = 0

2 sin 2x cos x + 2 Sin3x cosx= 0

2 [ sin 2x cos x + sin 3 x cos x ] =0

2 cos x [ sin 2x + sin 3x ] =0

2 cos x [ sin 5x/2 × cos x/2 ] = 0

cos x = 0

x = (2n + 1) π/2

sin5x/2 = 0

5x/2=nπ

x=2nπ/5

cos x/2=0

x/2=(2n+1)π/2

x=(2n+1)