Math, asked by Kunju743, 8 months ago

Solve solve solve!!!

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Answered by arnav3375

2

Answer:

tanA

Step-by-step explanation:

sinA(1-2sinA^2)/cosA(2cosA^2A-1)

sinA(1_2(1-cosA^2)/cosA(2cosA^2)

sinA(1-2+2cos^2A)/cosA(2cos^2A-1)

sinA(2cos^2A-1)/cosA(2cosA-1)

THEREFORE:sinA/cosA=tanA

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