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Let the tens digit of the required no.be X and the units digit be y. Then,
x+y = 9 (i)
Required no.= (10x + y)
Number obtained on reversing the digits= (10y+x)
therefore ;
(10y+x) - (10x+y)=27
9y - 9x=27
y-x=3 (ii)
on adding (i) and (ii)
2y = 12
y = 6
Putting the value of y in (i)
x+6 =9
x= 3
Hence the required no. is 36.
HOPE THIS HELPS YOU ❤️❤️❤️❤️❤️
x+y = 9 (i)
Required no.= (10x + y)
Number obtained on reversing the digits= (10y+x)
therefore ;
(10y+x) - (10x+y)=27
9y - 9x=27
y-x=3 (ii)
on adding (i) and (ii)
2y = 12
y = 6
Putting the value of y in (i)
x+6 =9
x= 3
Hence the required no. is 36.
HOPE THIS HELPS YOU ❤️❤️❤️❤️❤️
piyushsp8017:
mark as brainliest please☺️
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