Question

Solve solve solve solve​

Answer 1

Answer:

p(x)=0

x³+2x²-5x-6=0

(-1)³+2(-1)²-5(-1)-6=0

-1+2+5-6=0

-1+7-6=0

7-7=0

0=0

L.H.S=R.H.S

Therefore,x+1 is a factor

p(x)=0

x³+2x²-5x-6=0

(2)³+2(2)²-5(2)-6=0

8+8-10-6=0

16-16=0

0=0

L.H.S=R.H.S

Therefore,x-2 is a factor

p(x)=0

x³+2x²-5x-6=0

(-3)³+2(-3)²-5(-3)-6=0

-27+18+15-6=0

33 - 33=0

0=0

L.H.S=R.H.S

Therefore,x+3 is a factor