Question

solve solve the following pairs of equation by reducing them to a pair of linear equation :

$\frac{1}{3x + y} + \frac{1}{3x - y} = \frac{3}{4} \\ \\ \frac{1}{2(3x + y)} - \frac{1}{2(3x - y)} = \frac{ - 1}{8}$
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Answer 1

this ans is too long that's why I have done in my note book