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let
1/(2x + 3y) = a
1/(3x - 2y) = b
a/2 + 12b/7 = 1/2......(1)
7a + 4b = 2.............(2)
(1) x 14 - (2) x 6
7a + 24b = 7
42a + 24b = 12
----------------------
-35a = -5
a = 1/7
from (2)
7a + 4b = 2
7*1/7 + 4b. = 2
1 + 4b = 2
4b = 2 - 1
4b = 1
b = 1/4
now,
a = 1/7
1/(2x+3y) = 1/7
2x + 3y = 7................(3)
b = 1/4
1/(3x - 2y) = 1/4
3x - 2y = 4..............(4)
(3) x 2 + (4) x 3
4x + 6y = 14
9x - 6y = 12
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13x =. 26
x = 2
from (3)
2x + 3y = 7
4 + 3y = 7
3y = 3
y = 1
so, solutions are
x = 2, y = 1
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