Math, asked by shyamchahar85, 4 months ago

solve step by step can you solve i mark you these two question you solve ​

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Answered by Anonymous
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Question 7:

Mahavir takes 6 days to plough the field alone. What we can first do is figure out how much of the field he ploughs in a day.

1 field ÷ 6 days = \frac{1}{6} of the field

Therefore, Mahavir ploughs \frac{1}{6} of the field per day.

We know that Mahavir and Randhir take 4 days together. Since we know how much of the field Mahavir ploughs in a day, we can first calculate how much of the field Mahavir ploughs in 4 days:

4(\frac{1}{6} )=\frac{4}{6} = \frac{2}{3}

As shown above, Mahavir ploughs \frac{2}{3} of the field in 4 days when working alone.

Next, we need to calculate how much of the field Randhir ploughs in 4 days. We know that when Mahavir and Rhandir work together, they can plough 1 field in 4 days, therefore we will use addition.

In the equation below, x represents how much of the field Randhir ploughs per day:

(Fraction of field Mahavir ploughs per day × 4 days) + (Fraction of field Randhir ploughs per day × 4) = Mahavir and Randhir plough 1 field

\frac{2}{3}+4x=1\\\\4x=1-\frac{2}{3} \\4x=\frac{1}{3} \\x=\frac{1}{12}

Therefore, Randhir ploughs \frac{1}{12} of the field in a day.

In the equation below, y represents how many days it takes Randhir to plough one field alone.

\frac{1}{12} of the field × y days = 1 field

Try to figure out y by yourself. And question 8 follows the same concept.

Hope this helps!

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