Question

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for question refer the attachment.​

Answer 1

Answer:

bro it is some what tuff but I can do it

Answer 2

de-brogile wavelength of an electron is given by,

=√150/V and also by 12.25/√V.

$\frac{12.25}{ \sqrt{</em></strong><strong><em>V</em></strong><strong><em>} } = \frac{12.25}{ \sqrt{100 \times {10}^{6} } } = \frac{12.25}{ \sqrt{ {10}^{8} } } = \frac{12.25}{ {10}^{4} } \times {10 }^{ - 10} = 12.25 \times {10}^{ - 14} m$