solve step by step pls
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•(3÷2)^7÷(3÷2)^9
=a^m÷a^n=(a)^m-n
therefore,(3÷2)^7-9=(3÷2)^-2
•(3÷2)^-2×(3÷2)^2
=a^m×a^n=(a)^m+n
therefore,(3÷2)^(-2)+2=(3÷2)^0=1
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According to BODMAS,We shall first do division and then multiplication.
Hope it helps uuuu...
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