Question

solve:(substitution methods) 5x+4=4,x-20=12y​

Answer 1

Y=-3/2

X=8/5

5x+4y=4 ...... (1)

x-20=12 ..... (2)

=> 5x=4-4y

X=4-4y/5 ......(3)

substituting (3) in (2)

(4-4y/5)-20=12y

4-4y-100=60y

4-100=60y+4y

-96=64y

y= -96/64

y= -3/2 ........ (4)

Putting (4) in (3)

X= 4-4(-3/2)/5

X= 4+12/10

X= 16/10

X= 8/5

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Answer 2

Step-by-step explanation:

your answer is

x=8/5

y=-3/2

........