Question

solve system of linear using matrix method A-B+C=4
2A+B-3C=0
A+B+C=2 ​

Answer 1

Answer:

the answer in above photo hope so it's help you

Answer 2

Answer :-

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A-B+C = 4

A = 4+B-C

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2A+B-3C = 0

2(4+B-C)-3C = 0

8+2B-2C-3C = 0

8+2B = 5C

$8+2B = 5C \\ B = \frac{5C - 8}{2}$

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A+B+C = 2

$4 + \frac{5C - 8}{2} - C + \frac{5C - 8}{2} + C = 2 \\ \frac{8 + 5C - 8 - 2C + 5C - 8 + 2C}{2} = 2 \\ 10C - 8 = 4 \\ 10C = 12 \\ C = \frac{12}{10}$

$\implies \: B = \frac{6 - 8}{2} = -1$

$\implies \: A = 1.8$

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HOPE THIS HELPS YOU!!!!!