solve system of linear using matrix method A-B+C=4
2A+B-3C=0
A+B+C=2
Answers
Answered by
3
Perform the Gauss Jordan elimination on the augmented matrix
A
=
⎛
⎜
⎝
1
3
2
∣
3
2
−
1
−
3
∣
−
8
5
2
1
∣
9
⎞
⎟
⎠
I have written the equations not in the sequence as in the question in order to get
1
as pivot.
Perform the folowing operations on the rows of the matrix
R
2
←
R
2
−
2
R
1
;
R
3
←
R
3
−
5
R
1
A
=
⎛
⎜
⎝
1
3
2
∣
3
0
−
7
−
7
∣
−
14
0
−
13
−
9
∣
−
6
⎞
⎟
⎠
R
2
←
R
2
−
7
A
=
⎛
⎜
⎝
1
3
2
∣
3
0
1
1
∣
2
0
−
13
−
9
∣
−
6
⎞
⎟
⎠
R
3
←
R
3
+
13
R
2
A
=
⎛
⎜
⎝
1
3
2
∣
3
0
1
1
∣
2
0
0
4
∣
20
⎞
⎟
⎠
R
3
←
R
3
4
A
=
⎛
⎜
⎝
1
3
2
∣
3
0
1
1
∣
2
0
0
1
∣
5
⎞
⎟
⎠
R
1
←
R
1
−
2
R
3
;
R
2
←
R
2
−
R
3
A
=
⎛
⎜
⎝
1
3
0
∣
−
7
0
1
0
∣
−
3
0
0
1
∣
5
⎞
⎟
⎠
R
1
←
R
1
−
3
R
2
A
=
⎛
⎜
⎝
1
0
0
∣
2
0
1
0
∣
−
3
0
0
1
∣
5
⎞
⎟
⎠
Thus
a
=
2
,
b
=
−
3
and
c
=
5
hope it helps you ✌️✅✅✅
Similar questions