solve t^2 + 3*t =7 by square method
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t^2+3t=7
t^2+2×3t-7=0
t^2+2×3/2t+3t^2-7=0
(t-2/3)^2+(2/3)^2-7=(t-2/3)^2-1/49
t2/3=1/7
t=1/7-2/3 and t=1/7+2/3
t=3-14/21 and t=3+14/21
t=-11/21 and t=17/21
I hope it will help for u ☺.
t^2+2×3t-7=0
t^2+2×3/2t+3t^2-7=0
(t-2/3)^2+(2/3)^2-7=(t-2/3)^2-1/49
t2/3=1/7
t=1/7-2/3 and t=1/7+2/3
t=3-14/21 and t=3+14/21
t=-11/21 and t=17/21
I hope it will help for u ☺.
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