solve tan^-1(2x)+tan^-1(3x)=nπ/3π/4
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Answer:
X = tan×n/20
Step-by-step explanation:
tan^-1 (2x) + (3x) = nπ/3π/4
2x/tan +3x/tan = n/4
2x+3x/tan = n/4
5x/tan =n/4
5x × 4 = tan × n
20x = n × tan
x = n × tan/20
I don't know it's right or wrong but I tried.... I hope it helps u
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