Solve
tan 3 theata+ tan theata =2 tan 2 theata
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Step-by-step explanation:
Given tan 3 θ + tanθ = tan 2 θ Now putting the value of tan 3 θ and tan 2 θ we get , 3 tanθ - tan 3 θ 1 - 3 tan 2 θ + tanθ = 2 tanθ 1 - tan 2 θ 3 tanθ - tan 3 θ + tanθ - 3 tan 3 θ 1 - 3 tan 2 θ = 2 tanθ 1 - tan 2 θ 2 tanθ - 2 tan 3 θ 1 - 3 tan 2 θ = tanθ 1 - tan 2 θ 2 tanθ - 2 tan 3 θ - 2 tan 3 θ + 2 tan 5 θ = tanθ - 3 ...
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