solve tanx+tan4x+tan7x=tanx .tan4x .tan7x
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Given tanx+tan4x+tan7x=tanxtan4tan7x
We know that tan(a+b+c)=tana+tanb+tanc-tanatanbtanc/1-(tanatanb+tanbtanc+tanctana)
If a+b+c is n(pie),n belongs to N then tan(a+b+c)=0
=> tana+tanb+tanc-tanatanbtanc=0
=>tana+tanb+tanc=tanatanbtanc
it is same as the given question,
Hence , x+4x+7x=n(pie)
=>12x=n(pie)
=> x=n(pie)/12
We know that tan(a+b+c)=tana+tanb+tanc-tanatanbtanc/1-(tanatanb+tanbtanc+tanctana)
If a+b+c is n(pie),n belongs to N then tan(a+b+c)=0
=> tana+tanb+tanc-tanatanbtanc=0
=>tana+tanb+tanc=tanatanbtanc
it is same as the given question,
Hence , x+4x+7x=n(pie)
=>12x=n(pie)
=> x=n(pie)/12
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0
Answer:
it is the answer of tanx +tan4x+tan7x =tanx . tan4x .tan7x
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