Question

solve
$0 \leqslant x \leqslant 360 \\ \sqrt{3} cosx + sinx = \sqrt{3}$
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Answer 1

Answer:

\pink{\bold{\underline{ ✪ UPSC-ASPIRANT✪ }}}✪UPSC−ASPIRANT✪

\red{\bold{\underline{\underline{QUESTION:-}}}}QUESTION:−

Q:-

if \: c = \frac{a}{b} - \frac{d - e}{f - d}ifc=ba−f−dd−e

Find the value of f when a=3,b=4,c=-6,d=-5 & e=2

\huge\tt\underline\blue{Answer }Answer

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⟹ - 6 = \frac{3}{4} - \frac{( - 5) - 2}{f - ( - 5)}⟹−6=43−f−(−5)(−5)−2

⟹ - 6 = \frac{3}{4} - \frac{( -7)}{f + 5}⟹−6=43−f+5(−7)

⟹ - 6 = \frac{3}{4} + \frac{7}{f + 5}⟹−6=43+f+57

⟹ - 6 - \frac{3}{4} = \frac{7}{f + 5}⟹−6−43=f+57

⟹ \frac{ - 24 - 3}{4} = \frac{7}{f + 5}⟹4−24−3=f+57

⟹ - \frac{27}{4} = \frac{7}{f + 5}⟹−427=f+57

⟹ - 27(f + 5) = 28⟹−27(f+5)=28

⟹ - 27f - 135 = 28⟹−27f−135=28

⟹ - 27f = 28 + 135⟹−27f=28+135

⟹ - 27f = 163⟹−27f=163

⟹f = \frac{163}{ - 27}⟹f=−27163

∴f = - \frac{163}{27}f=−27163

════════════XXX═════════════

HOPE IT HELPS YOU..

_____________________

Thankyou:)

Explanation:

\pink{\bold{\underline{ ✪ UPSC-ASPIRANT✪ }}}✪UPSC−ASPIRANT✪

\red{\bold{\underline{\underline{QUESTION:-}}}}QUESTION:−

Q:-

if \: c = \frac{a}{b} - \frac{d - e}{f - d}ifc=ba−f−dd−e

Find the value of f when a=3,b=4,c=-6,d=-5 & e=2

\huge\tt\underline\blue{Answer }Answer

_ _ _ _ _ _ _ _ _ _ _ _ _ _ _✍️

════════════XXX═════════════

⟹ - 6 = \frac{3}{4} - \frac{( - 5) - 2}{f - ( - 5)}⟹−6=43−f−(−5)(−5)−2

⟹ - 6 = \frac{3}{4} - \frac{( -7)}{f + 5}⟹−6=43−f+5(−7)

⟹ - 6 = \frac{3}{4} + \frac{7}{f + 5}⟹−6=43+f+57

⟹ - 6 - \frac{3}{4} = \frac{7}{f + 5}⟹−6−43=f+57

⟹ \frac{ - 24 - 3}{4} = \frac{7}{f + 5}⟹4−24−3=f+57

⟹ - \frac{27}{4} = \frac{7}{f + 5}⟹−427=f+57

⟹ - 27(f + 5) = 28⟹−27(f+5)=28

⟹ - 27f - 135 = 28⟹−27f−135=28

⟹ - 27f = 28 + 135⟹−27f=28+135

⟹ - 27f = 163⟹−27f=163

⟹f = \frac{163}{ - 27}⟹f=−27163

∴f = - \frac{163}{27}f=−27163

════════════XXX═════════════

HOPE IT HELPS YOU..

_______________

Thankyou