Math, asked by sreekarreddy91, 2 months ago

Solve :-

1. \:  \sf  \frac{9}{8}   \: \div  \:  \frac{6}{2}

 \sf 2. \:  \frac{4}{8}  \:  \div  \:  \frac{1}{3}

  \mathbf {3. \:  \frac{23}{4} \:  \div  \:  \frac{8}{7}  }

 \rm 4.  \: \frac{16}{8}  \:  \div  \:  \frac{17}{4}
 \tt  5. \:  \frac{14}{8}  \:  \div   \:  \frac{7}{9}

Answers

Answered by tennetiraj86
7

Step-by-step explanation:

Given :-

1)(9/8)÷(6/2)

=>(9/8)÷3

=>9/(8×3)

=>3/8

(9/8)÷(6/2)=3/8

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2)(4/8)÷(1/3)

=>(2)×(3/1)

=>2/3

(4/8)÷(1/3)=2/3

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3)(23/4)÷(8/7)

=>(23/4)×(7/8)

=>(23×7)/(4×8)

=>161/32

(23/4)÷(8/7)=161/32

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4)(16/8)÷(17/4)

=>2÷(17/4)

=>2×(4/17)

=>(2×4)/17

=>8/17

(16/8)÷(17/4)=8/17

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5)(14/8)÷(7/9)

=>(7/4)÷(7/9)

=>(7/4)×(9/7)

=>(7×9)/(4×7)

=>9/4

(14/8)÷(7/9)=9/4

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Answered by Anonymous
61

Required Answer:-

(1) Ques: \sf\dfrac{9}{8} \div \sf\dfrac{6}{2}

Ans:

 \begin{gathered}:\implies\sf\dfrac{9}{8} \div \sf\dfrac{6}{2} \\  \\  \\  :\implies\sf\dfrac{\cancel{9}^{3}}{8}  \times \sf\dfrac{\cancel{2}^{1}}{\cancel{6_2}} \\\\\\ :\implies\sf\dfrac{3}{8}\end{gathered}

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(2) Ques: \sf\dfrac{4}{8} \div \sf\dfrac{1}{3}

Ans:

:\implies\sf\dfrac{4}{8} \div \sf\dfrac{1}{3}

:\implies\sf\dfrac{4}{8} \times \sf\dfrac{3}{1}

:\implies\sf {\cancel  \dfrac{12}{8} } =  \dfrac{3}{2}

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(3) Ques: \sf \dfrac{23}{4}  \div  \dfrac{8}{7}

Ans:

\begin{gathered}:\implies \: \sf  \dfrac{23}{4}  \div  \dfrac{8}{7} \\  \\  \\ : \implies \sf\dfrac{23}{4}   \times  \dfrac{7}{8}  \\  \\  \\  :\implies \:  \sf \dfrac{161}{28} \end{gathered}

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(4) Ques:

Ans:

\begin{gathered}:\implies\sf \dfrac{16}{8}  \div  \dfrac{17}{4}  \\  \\  \\ :\implies\sf  \dfrac{\cancel{16}^{2}}{\cancel{8_1}}  \times  \dfrac{4}{17}  \\  \\  \\ :\implies\sf  \frac{8}{17} \end{gathered}

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(5) Ques:  \sf\dfrac{14}{8} \div \dfrac{7}{9}

Ans:

 :\implies\sf\dfrac{14}{8} \div \dfrac{7}{9}

 :\implies\sf\dfrac{\cancel{14}^{2}}{8} \times \dfrac{9}{\cancel{7_1}}

 :\implies\sf\dfrac{18}{8}

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  • Remember , Whenever the Question is Asked in Division Operators so, We have to reciprocal the Given Second Value.
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