Question

solve:
${2x}^{2} + ax - {a}^{2} = 0$
by using b²-4ac method​

Answer 1

Step-by-step explanation:

Solution:-

eq=2x²+ax-a²

comparing it with ax²+bx+c =0,we get

a=2, b=a and c= -a²

Discriminant

D=b²-4ac=(a)²-4×2×-a²= a²+8a²=9a²

D=9a²

using quadratic formula

$x = \frac{ - b \pm \sqrt{d} }{2a}$

put the value in this formula

$x = \frac{ - a \pm \sqrt{9 {a}^{2} } }{2 \times 2 }$

$x = \frac{ - a \pm3a}{4}$

$x = \frac{ - a + 3a}{4} \: and \: \frac{ - a - 3a}{4}$

$x = \frac{2a}{4} \: and \: \frac{ - 4a}{4}$

value of x =a/2 and -a