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Hii let's solve this:
Simplify
(2x+3)(x_4)=6
2x^2_8x+3x_12=6
2x^2_5x_12=6
Transpose 6 to LHS
so we will get
2x^2_5x_18=0
Hence the final equation is 2x^2_5x_18=0
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