Question

solve
$(2x - \frac{1}{2} ) ^{2} = \frac{9}{4}$
​

Answer 1

Answer:

(4x+2)(x-1)

Step-by-step explanation:

(2x-1/2)^2 = 9/4

=> (2x)^2 + (1/2)^2 - 2*2x*1/2 = 9/4

=> 4x^2 + 1/4 -2x = 9/4

=> 4x^2 - 2x +1/4 - 9/4 = 0

=> 4x^2 - 2x - 8/4 = 0

=> 4x^2 - 2x -2 = 0

=> 4x^2 -4x + 2x -2 = 0

=> 4x (x-1) +2 ( x-1) = 0

=> (4x+2)(x-1) answer

I hope it is useful for you.

Plz give 10♥

Answer 2

Answer:

$x=\frac{-1}{2}$   (or)  $x=1$

Step-by-step explanation:

$(2x-\frac{1}{2}) ^{2} =\frac{9}{4}$

⇒ $(2x)^{2} +(\frac{1}{2} )^{2} -2(2x)(\frac{1}{2} )=\frac{9}{4}$              [∵$(a-b)^{2} =a^{2} +b^{2} -2ab$]

⇒ $4x^{2} +\frac{1}{4} -2x=\frac{9}{4}$

⇒ $4x^{2} -2x -\frac{8}{4} =0$

⇒ $4x^{2} -2x-2=0$            [this is in the form of quadratic equation]

⇒ $4x^{2} -4x+2x-2$

⇒ $4x(x-1)+2(x-1)$

⇒ $(4x+2)(x-1)$

∴ $x=\frac{-1}{2}$   (or) $x=1$

Hope this helps you❤❤❤