Question

Solve

$3x {}^{2} - 2 \sqrt{6x} + 2$


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Answer 1

AnswEr:

value of x is : $\bold{\sf{\sqrt{\dfrac{2}{3}}}}$

ExplanaTion:

Given polynomial : 3x² - 2√6x + 2 = 0

By splitting middle term,

: $\implies$ 3x² - √6x - √6x + 2 = 0

: $\implies$ √3x ( √3x - √2 ) - √2 ( √3x - √2 ) = 0

: $\implies$ ( √3x - √2 ) ( { √3x - √2 ) = 0

: $\implies$ ( √3x - √2 ) = 0 and ( √3x - √2 ) = 0

: $\implies$ √3x = √2 and √3x = √2

: $\implies$ x = $\sf{\sqrt{\dfrac{2}{3}}}$ and x = $\sf{\sqrt{\dfrac{2}{3}}}$

Hence, value of x is : $\bold{\sf{\sqrt{\dfrac{2}{3}}}}$

Answer 2

$\large \underline{ \red{ \boxed{ \bf \orange{Required \: Answer}}}}$