Math, asked by ayeshadargahwala, 1 year ago

solve
 {4}^{x}  - 5  \times  {2}^{x}  + 4 = 0

Answers

Answered by BendingReality
11

Answer:

0 or 2

Step-by-step explanation:

Given :

4ˣ - 5 × 2ˣ + 4 = 0

2ˣ × 2ˣ - 5 × 2ˣ + 4 = 0

Let 2ˣ = y

y² - 5 y + 4 = 0

y² - 4 y - y + 4 = 0

y ( y - 4 ) - ( y - 4 ) = 0

( y - 1 ) ( y - 4 ) = 0

y - 1 = 0

y = 1

OR

y - 4 = 0

y = 4

Now on comparing :

2ˣ = 4

2ˣ = 2²

x = 2

OR

2ˣ = 1

2ˣ = 2⁰

x = 0

Therefore , the value of x is 0 OR 2 .

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