Question

solve :-

$45 = {2k}^{2} + 3k + 1$

Answer 1

your answer is here.....
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Answer 2

SOLUTION

Given:

$2 k^2 + 3 k + 1 = 45$

$\implies 2 k^2 + 3 k + 1 - 45 = 0$

$\implies 2 k^2 + 3 k - 44 = 0$

$\implies 2 k^2 - 8 k + 11 k -44 = 0$

$\implies 2 k ( k - 4 ) + 11 ( k - 4 ) = 0$

$\implies ( 2k + 11)( k - 4) = 0$

Either $2 k + 11 = 0$

$\implies 2 k = -11$

$\implies k = \frac{-11}{2}$

or .  $k - 4 =0$

$k = 4$

The values of k are :

$\sf{The\:values\:of\:k\:are}\:\boxed{4}\:\sf{and\:}\boxed{-\frac{11}{2}}$

Hope it helps you :-)

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