Question

Solve
$49 {x }^{2} + 21x \ + \frac{9}{4} = 0$
by using method of completing square.
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Answer 1

Answer:

49x^2 + 21x + 9/4

(7x)^2 + 2 × 7 × 3/2 +( 3/2)^2

(7x + 3/2)^2

(7x + 3/2)(7x + 3/2)

Answer 2

The quadratic eqn will have two real and equal roots

I.e,

x = -3/14

●REFER TO THE ATTACHMENT FOR SOLUTION●