Question

solve
$4x {}^{4} - 3x {}^{2 } + 1$
​

Answer 1

Step-by-step explanation:

${4x}^{4} - {3x}^{2} + 1 \\ = > {x}^{2} + 1 = 0 \\ = > {x}^{2} = - 1 \\ x = \sqrt{ - 1} \\ x = 1$

Answer 2

Answer:

$\sqrt{x} = - 1 \\ \sqrt{x} = 1$