Question

solve :
$6x {}^{2} + 40 = 31x$
​

Answer 1

Answer:

It's solution is in mathematics guide of your class grade

Answer 2

Step-by-step explanation:

Heya!!

The equation may be written as 6x²-31x+40 = 0.

Then,

⇒6x²-31x+40 = 0

⇒6x²-16x-15x+40 = 0

⇒2x(3x-8) -5(3x-8) = 0

⇒(3x-8) (2x-5) = 0

⇒3x-8 = 0 or 2x-5 = 0

⇒$x= \frac{8}{3} \: or \: x= \frac{5}{2}$

Hence, $\frac{8}{3} \: and \: \frac{5}{2}$ are the roots of the given equation.