Question

solve:-
${7x}^{2} + 5x + 3$
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Answer 1

Solution :-

By using quadratic formula

$\implies \underline{ \boxed{\bf x = \dfrac{ - b\pm \sqrt{ {b}^{2} - 4ac} }{2a}}}$

Here

a = 7

b = 5

c = 3

Substitute values in formula

$\begin{gathered}\implies \sf x = \dfrac{ - 5\pm \sqrt{ {5}^{2} - 4 \times 7 \times 3} }{2 \times 7} \\ \\ \implies \sf x = \dfrac{ - 5\pm \sqrt{25 - 63} }{21} \\ \\ \implies \sf x = \dfrac{ - 5\pm \sqrt{ - 35} }{21}\end{gathered}$

Talking +ve sign

$\implies \sf x = \dfrac{ - 5 - \sqrt{ 35} }{21}$

Taking - ve sign

$\implies \sf x = \dfrac{ - 5 + \sqrt{ 35} }{21}$

Answer 2

Step-by-step explanation:

Solution :-

By using quadratic formula

\implies \underline{ \boxed{\bf x = \dfrac{ - b\pm \sqrt{ {b}^{2} - 4ac} }{2a}}}⟹

x=

2a

−b±

b

2

−4ac

Here

a = 7

b = 5

c = 3

Substitute values in formula

\begin{gathered}\begin{gathered}\implies \sf x = \dfrac{ - 5\pm \sqrt{ {5}^{2} - 4 \times 7 \times 3} }{2 \times 7} \\ \\ \implies \sf x = \dfrac{ - 5\pm \sqrt{25 - 63} }{21} \\ \\ \implies \sf x = \dfrac{ - 5\pm \sqrt{ - 35} }{21}\end{gathered}\end{gathered}

⟹x=

2×7

−5±

5

2

−4×7×3

⟹x=

21

−5±

25−63

⟹x=

21

−5±

−35

Talking +ve sign

\implies \sf x = \dfrac{ - 5 - \sqrt{ 35} }{21}⟹x=

21

−5−

35

Taking - ve sign

\implies \sf x = \dfrac{ - 5 + \sqrt{ 35} }{21}⟹x=

21

−5+

35