solve:-
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Solution :-
☑ ԻḙḟḙԻ т✺ тℏḙ ᾰттᾰḉℏՊḙℵт ❤
☑ thus y = -1 and -4/3
❤Ⓗⓞⓟⓔ ⓘⓣ ⓗⓔⓛⓟⓢ❤
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7y = -3y^2 - 4
7y + 3y^2 + 4 = 0
3y^2 + 7y + 4 = 0
3y^2 +(3 + 4) y +4 =0
3y^2 + 3y + 4y + 4 = 0
3y ( y + 1 ) + 4 ( y + 1 ) = 0
( 3y + 4 ) ( y + 1 ) = 0
y = -4/3 , y = -1
I hope it will help you
Make my answer as a brainliest
7y + 3y^2 + 4 = 0
3y^2 + 7y + 4 = 0
3y^2 +(3 + 4) y +4 =0
3y^2 + 3y + 4y + 4 = 0
3y ( y + 1 ) + 4 ( y + 1 ) = 0
( 3y + 4 ) ( y + 1 ) = 0
y = -4/3 , y = -1
I hope it will help you
Make my answer as a brainliest
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