Question

solve
$98 \times (3.14 \div 8 - 1 \div 2 \sqrt{2)}$
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Answer 1

Simplify:

Step-by-step explanation:

$\ Given \ value:\\\\\ 98 \times (3.14\div 8- 1 \div 2\sqrt{2})\\\\ \ Solution: \\\\\rightarrow \ 98 \times (\frac{3.14}{8} \ - \frac{1}{2\sqrt{2}})\\\\\rightarrow \ 98 \times (\frac{3.14}{8} \ - \frac{1}{2\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}})\\\\\rightarrow \ 98 \times (\frac{3.14}{8} \ - \frac{\sqrt{2}}{4})\\\\\rightarrow \ 98 \times (\frac{3.14-2\sqrt{2}}{8})$

$\therefore \sqrt{2} =1.41 \\\\\rightarrow \ 98 \times (\frac{3.14-2\times 1.41}{8})\\\\ \rightarrow \ 98 \times (\frac{3.14-2.82}{8})\\\\ \rightarrow \ 98 \times \frac{0.32}{8}\\\\ \rightarrow \ 49 \times \frac{0.32}{4}\\\\\rightarrow \frac{15.68}{4}\\\\\rightarrow \ 3.92$

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